IslandT: Return how many times each letter shows up in the string by using an asterisk (*)

Hello people, in this article we will solve the below python problem.

You receive the name of a city as a string, and you need to return a string that shows how many times each letter shows up in the string by using an asterisk (*).

For example:

“Chicago” –> “c:*,h:,i:,a:,g:,o:“

As you can see, the letter c is shown only once, but with 2 asterisks.

The return string should include only the letters (not the dashes, spaces, apostrophes, etc). There should be no spaces in the output, and the different letters are separated by a comma (,) as seen in the example above.

Note that the return string must list the letters in order of their first appearance in the original string.

I will solve the above problem using just a pure/core python module without importing any extra module.

def get_strings(city):

    city = "".join(city.lower().split()) # get rid of all spaces and turn all characters into lower case characters

    city_list = list(city) # next turn the city string into a list

    already = [] # this is used to hold the character which has already counted before

    city_string = '' # this is the city string which will be returned

    for word in city_list:

        if word not in already:

            count = city_list.count(word)
            city_string += word + ":"

            for i in range(0, count):
                city_string += "*"

            city_string+= ","
            already.append(word)

    return city_string[:-1] # don't forget to get rid of the last comma

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Do you like the above solution or do you have a better one? Let me know in the comment box below this post!

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